Pyramid of broken strings

Question

Given a string n, create a pyramid of the string split into pieces relative to the current row.

The first row contains the string unmodified.

The second row contains the string separated into halves by a pipe.

The third row separates it by thirds...

And so on. The length of each substring, where l is the length of string n is equal to

floor(l/n)

Characters left over are put in their own substring. The last row used is the first one where substrings are 2 in length.

Test Cases:

Input: Hello, world.

Output:

Hello, world.

Hello,| world|.

Hell|o, w|orld|.

Hel|lo,| wo|rld|.

He|ll|o,| w|or|ld|.

---

Input: abcdefghij

Output:

abcdefghij

abcde|fghij

abc|def|ghi|j

ab|cd|ef|gh|ij

---

Input: 01234567890abcdef

Output:

01234567890abcdef

01234567|890abcde|f

01234|56789|0abcd|ef

0123|4567|890a|bcde|f

012|345|678|90a|bcd|ef

01|23|45|67|89|0a|bc|de|f

---

Extra rules:

• You can write a full program or a function, whichever uses less code.

• Input will always be at least 4 characters in length.

• You MUST use line breaks if your language supports them. If not possible, replace line breaks with :

• Input will always be printable ASCII.

• Minus 100% if your program solves P vs. NP.

---

Leaderboard:

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Answer 1

Perl, 46 + 1 = 47 bytes

Run with the -n flag

say s/.{$=}(?=.)/$&|/gr while($==y///c/++$,)-2

Try it online!

Code breakdown

-n                                              #Reads input into the $_ variable
say s/.{$=}(?=.)/$&|/gr while($==y///c/++$,)-2
                                 y///c          #Transliteration.  Implicitly operates on $_, replacing every character with itself and counting replacements
                                                #y///c effectively returns the length of $_
                                      /++$,     #Increments $, (which starts off at 0) and divides the length of $_ by $,
                              $==               #Stores the result of this division into $=
                                                #$= forces its contents to be an integer, so it truncates any decimal
                             (             )-2  #Returns 0 if $= is equal to 2
                        while                   #Evaluates its RHS as the condition.  If truthy, evaluates its LHS.
    s/          /   /gr                         #Substitution.  Implicitly operates on $_.
                                                #Searches for its first argument and replaces it with its second argument, repeating until it's done, and returns the new string.  $_ is not modified.
      .{$=}                                     #Looks for a string of $= characters...
           (?=.)                                #...that is followed by at least one non-newline character, but does not include this character in the match...
                 $&|                            #...and replaces it with itself followed by a pipe character.
say                                             #Output the result of the substitution.

Answer 2

Pyth, 16 bytes

Vh/lQ3j\|cQ/lQhN

V                # For N in range(1, \/ )
 h/lQ3           # 1+lenght(input)/3
      j\|        # join with '|'
         cQ      # chop input in
           /lQhN # lenght(input)/(N+1) pieces

try here

Answer 3

C, 145 131 128 125 bytes

l,n,i=1,j;f(char*s){l=strlen(s);puts(s);do{n=l/++i;for(j=0;j<l;)j&&(j%n||putchar('|')),putchar(s[j++]);puts("");}while(n>2);}

This is a function that takes a string as its argument and prints the output to STDOUT.

l,n,i=1,j;       // declare some variables
f(char*s){       // declare the function
l=strlen(s);     // get the length of the string
puts(s);         // output the initial version, with trailing newline
do{n=l/++i;      // n is the number of characters per "section",
                 //  and we'll do-while n>2 to stop at the right time
for(j=0;j<l;)    // loop through the characters of the string
j&&(             // if j != 0,
j%n||            // and j % n == 0,
putchar('|')),   // insert a | before this character
putchar(s[j++]); // print the character
puts("");        // print a newline after the loop
}while(n>2);}

Answer 4

Pyth, 17 bytes

jmj\|cQ/lQdSh/lQ3

Explanation

     cQ/lQ         Divide into equal pieces (with the last shorter)
  j\|              Join with pipes
 m        d        Map to each row index...
           Sh/lQ3  ... up to the first row with substrings of length 2
j                  Join with newlines

Answer 5

Javascript, 98 Bytes

a=>{for(b=1;2<=a.length/b;)eval("console.log(a.match(/.{1,"+(a.length/b|0)+"}/g).join('|'))"),b++}

Function x(a). Call using

console.log(x("ABCDEF"))

Answer 6

JavaScript (ES6), 103 101 91 84 bytes

Fixed to respect challenge requirements

f=(s,n=0,p=s.length/++n|0)=>p>1?s.match(eval('/.{1,'+p+'}/g')).join`|`+'\n'+f(s,n):''

Lambda f that takes input string as first parameter s and recursively prints to console the split string. Pretty straightforward: as long as the substring length, p, is above 1, print the string split by a '|' every p characters, then proceed with appending the following level. This then calls the function again with p being t / n floored, where t is the original string length and n being an incremented divider.

Answer 7

Python 3, 123 bytes

f=lambda s:print(*['|'.join(s[i:i+n]for i in range(0,len(s),n))for n in[len(s)//i for i in range(1,len(s)//2+1)]],sep='\n')

At longer strings some parts will be repeated, as the formula for the length of the substring is floor(l/n). For example with a string 13 chars long, the string split into 5's would be the same as the string split into 6's as floor(13/5)==floor(13/6). I'm not sure if the OP expected this or if it was an oversight.

Answer 8

Ruby -n, 60 bytes

z= ~/$/
(z/3+1).times{|n|puts $_.scan(/.{1,#{z/(n+1)}}/)*?|}

Attempt This Online!

Answer 9

Vyxal, 13 bytes

₌LżḭvẇUṪ\|vj⁋

Try it Online!

12 with j flag

Explained

₌LżḭvẇUṪ\|vj⁋
₌Lż            # Push len(input) and [1..len(input)]
   ḭ           # Floor divide the length by each number in the range
    vẇ         # And wrap the input into chunks of each length
      UṪ       # Uniquify the list and remove the last item (which will be the input split into chunks of length 1)
        \|vj   # Join each list on "|"
            ⁋  # And join that on newlines