Constant output program

Question

I was wondering how one might go and produce a program that takes input from some kind of random source and uses it to produce constant output. An obvious way is, for example, to take an integer x and output x/x for 1, but that isn't too clever, is it? Therefore, the task is to write a program that outputs the same thing, no matter which input is given to it.

Specifications

• The program may assume that the input is either a number or a one line string (that is, valid characters are [a-z][A-z][0-9] and spaces). If you adopt one of those restrictions, specify which in your answer.
• The program must use the entered input in some way. To put it more formally, the contents of the variable that takes the input must be used afterwards in some calculation that affects the final variable to be printed.

The winner will be the most upvoted solution.

Answer 1

Python

This question is boring. I'd rather sleep.

from time import sleep
sleep(input())

Input a number.

Answer 2

GolfScript

~{.3*){.2%}{2/}until.@=!}do

This program will take a positive integer as input, and will output 1 unless the input is a counterexample to the Collatz conjecture. While the Collatz conjecture remains an open problem, it is known that there are no counterexamples below 5 × 2⁶⁰.

Answer 3

Perl

<>/0

produces for any input string:

Illegal division by zero at test5.pl line 1, <> line 1.

Answer 4

J

=

Usage:

   =10
1

Always outputs 1.

Or how about an unhappy smiley verb:

{:0[

Usage:

   {:0[ 147
0

Always ouputs 0.

Answer 5

Python

n=input()
p=37
print (n**p-n)%p

Takes an integer input, and always outputs 0. Uses Fermat's little theorem, which states that n^p == n mod p.

Answer 6

Javascript

var input = ~~prompt("Input an integer!");
if(Math.abs(input)<=Math.pow(2,31))
  console.log("It's too small! (not bigger than 2^31 = "+Math.pow(2,31)+")");
else console.log("It's quite big!");

Though JS can represent any integer between ±9,007,199,254,740,992, it will always print

It's too small! (not bigger than 2^31 = 2147483648)

because bitwise operation is performed in range of 32bit.

Answer 7

Python 2

x=input()
print x^x

Only accepts integers. always outputs 0 by xoring itself

Answer 8

Golfscript

.=

Accepts any input and always prints 1.

Answer 9

Ruby:

p !gets

Always outputs false. gets takes user input, ! negates that and since strings are truthy, the result will be false.

Answer 10

Ruby

def a(x)
  4
end

I somehow felt this was related:

Answer 11

Python

def f(x):    
    return 0*x

Answer 12

JavaScript

var input = prompt("Input something!");

console.log(new Number(input) === 1);

Will always return false, even with the input 1

Answer 13

Golfscript (4 chars)

~1\?

Accepts an integer. Outputs 1.

Answer 14

Perl

$a=<>+1;for(1..length$a){$a=length$a}print$a

This program does use the input number, and it always prints 1.

Answer 15

Python

print float("inf")*sum(map(ord,raw_input()))

Always returns 'infinity'.

Answer 16

Q

Returns 1. Where no parameters are declared, Q implicitly uses x,y& z where appropriate. I think this satisfies the second condition...

{1}

Answer 17

Python

print input()*0

Answer 18

Python

This one works for numbers only.
I can't prove that it works for all numbers (can anyone?), but it prints "False" for all cases I've tested.
EDIT: Fixed a bug in the last line.

p=lambda x:x>1 and (i*i>x for i in xrange(2,x+1) if x%i==0 or i*i>x).next()
q=lambda x:(i<x for i in xrange(2,x+1) if p(i) and p(x-i) or i==x).next()
x = input()
print x%2==0 and x>2 and not q(x)

Explanation (for those who think my Python code is unclear):
p(x) tells you if x is a prime.
q(x) looks for two primes, whose some is x.
The program prints True if the number is even, greater than 2 and not the sum of 2 primes.
Please tell me if you find such a number.

Answer 19

C

Produces 1 (prints and returns) for every input. (Input being the number of command line args)

j;main(c){j=0;while(c){j+=c%2;c/=2;}return j^1?main(j):printf("%d",j);}

This program does the same #error 1 but cannot properly speaking be said to take input (unless you count the rest of the program after as input).

Answer 20

Python

print eval('42#'+raw_input())

Accepts any input